This function calculates the cross product of two vectors, and returns the result as a pipe-bar delimited list.
VectorCross([Vector 1], [Vector 2])
Where:
Vector 1 is a pipe-bar delimited list representing the first vector (X|Y|Z).
Vector 2 is a pipe-bar delimited list representing the second vector (X|Y|Z).
| Rule | Result |
|---|---|
| VectorCross("1|1|1","2|8|5") | Will return the cross product of the two vectors, -3|-3|6. |
Due to floating point precision, some calculations may not be as precise as expected.
This can be avoided by following the advice in the topic Info: Floating Point Precision.