This function subtracts the second vector from the first, and returns the result as a pipe-bar delimited list.
VectorSubtract([Vector 1], [Vector 2])
Where:
Vector 1 is a pipe-bar delimited list representing the first vector (X|Y|Z).
Vector 2 is a pipe-bar delimited list representing the second vector (X|Y|Z).
Rule | Result |
---|---|
VectorSubtract("5|8","2|1") | Will return the result of the two subtracted 2D vectors, 3|7. |
VectorSubtract("5|8|13","2|1|4") | Will return the result of the two subtracted 3D vectors, 3|7|9. |
Due to floating point precision, some calculations may not be as precise as expected.
This can be avoided by following the advice in the topic Info: Floating Point Precision.